Tuesday, 17 February 2015

Formulae for Trains Problem

    • km/hr to m/s conversion:
      a km/hr =a x5m/s.
      18
    • m/s to km/hr conversion:
      a m/s =a x18km/hr.
      5
    • Formulas for finding Speed, Time and Distance
    • Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres.
    • Time taken by a train of length l metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres.
    • Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
    • Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
    • If two trains of length a metres and b metres are moving in opposite directions at um/s and v m/s, then:
      The time taken by the trains to cross each other =(a + b)sec.
      (u + v)
    • If two trains of length a metres and b metres are moving in the same direction at um/s and v m/s, then:
      The time taken by the faster train to cross the slower train =(a + b)sec.
      (u - v)
    • If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then:
      (A's speed) : (B's speed) = (b : a)

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